x+4y^2-8=0

Lösung

x + 4 y^{2} - 8 = 0

(h, k) = (8, 0), p = - \frac{1}{16}

Schritte zur Lösung

x + 4 y^{2} - 8 = 0

Rewrite

x + 4 y^{2} - 8 = 0

in the standard form:

4 (- \frac{1}{16}) (x - 8) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (8, 0), p = - \frac{1}{16}

x - 1 = (y + 5)^{2}

7 x^{2} + y = 13

x^{2} + 20 y = 10

y^{2} = x - 9

0 = (y - 1)^{2} - 16 (x + y)