What is x^2+8x+y^2+15=0 ?

The solution to x^2+8x+y^2+15=0 is Circle with (a,b)=(-4,0),r=1

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x^2+8x+y^2+15=0

x^{2} + 8 x + y^{2} + 15 = 0

(a, b) = (- 4, 0), r = 1

Solution steps

x^{2} + 8 x + y^{2} + 15 = 0

Rewrite

x^{2} + 8 x + y^{2} + 15 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 4, 0), r = 1

(x - 3)^{2} + (y + 3)^{2} = 6^{2}

4 x^{2} - 4 x + 4 y^{2} + 4 y = 9

x^{2} + y^{2} - 2 x + 6 y - 6 = 0

y^{2} + x^{2} - 2 x + 12 y - 12 = 0

4 x^{2} + 4 y^{2} + 40 x - 32 y - 5 = 0

What is x^2+8x+y^2+15=0 ?
The solution to x^2+8x+y^2+15=0 is Circle with (a,b)=(-4,0),r=1