What is (x-3)^2+(y+3)^2=6^2 ?

The solution to (x-3)^2+(y+3)^2=6^2 is Circle with (a,b)=(3,-3),r=6

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(x-3)^2+(y+3)^2=6^2

(x - 3)^{2} + (y + 3)^{2} = 6^{2}

(a, b) = (3, - 3), r = 6

Solution steps

(x - 3)^{2} + (y + 3)^{2} = 6^{2}

Rewrite

(x - 3)^{2} + (y + 3)^{2} = 6^{2}

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 3))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (3, - 3), r = 6

4 x^{2} - 4 x + 4 y^{2} + 4 y = 9

x^{2} + y^{2} - 2 x + 6 y - 6 = 0

y^{2} + x^{2} - 2 x + 12 y - 12 = 0

4 x^{2} + 4 y^{2} + 40 x - 32 y - 5 = 0

4 x^{2} + 4 y^{2} - 20 x + 40 y = - 5

What is (x-3)^2+(y+3)^2=6^2 ?
The solution to (x-3)^2+(y+3)^2=6^2 is Circle with (a,b)=(3,-3),r=6