What is y^2+x^2-2x+12y-12=0 ?

The solution to y^2+x^2-2x+12y-12=0 is Circle with (a,b)=(1,-6),r=7

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y^2+x^2-2x+12y-12=0

y^{2} + x^{2} - 2 x + 12 y - 12 = 0

(a, b) = (1, - 6), r = 7

Solution steps

y^{2} + x^{2} - 2 x + 12 y - 12 = 0

Rewrite

y^{2} + x^{2} - 2 x + 12 y - 12 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 6))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (1, - 6), r = 7

4 x^{2} + 4 y^{2} + 40 x - 32 y - 5 = 0

4 x^{2} + 4 y^{2} - 20 x + 40 y = - 5

4 x^{2} + 4 y^{2} + 6 x + 8 y - 5 = 0

(x - 1)^{2} + (y - 2)^{2} = 10

x^{2} + y^{2} - 14 x + 38 = 0

What is y^2+x^2-2x+12y-12=0 ?
The solution to y^2+x^2-2x+12y-12=0 is Circle with (a,b)=(1,-6),r=7