What is (x-1)^2+(y-2)^2=10 ?

The solution to (x-1)^2+(y-2)^2=10 is Circle with (a,b)=(1,2),r=sqrt(10)

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(x-1)^2+(y-2)^2=10

(x - 1)^{2} + (y - 2)^{2} = 10

(a, b) = (1, 2), r = 10

Solution steps

(x - 1)^{2} + (y - 2)^{2} = 10

Rewrite

(x - 1)^{2} + (y - 2)^{2} = 10

in the form of the standard circle equation

(x - 1)^{2} + (y - 2)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (1, 2), r = 10

x^{2} + y^{2} - 14 x + 38 = 0

x^{2} + y^{2} + 4 x - 5 = 0

x^{2} - 4 x + 6 y + y^{2} = 4

x^{2} + y^{2} + 6 x + 8 y + 24 = 0

2 x^{2} + 2 y^{2} = 8

What is (x-1)^2+(y-2)^2=10 ?
The solution to (x-1)^2+(y-2)^2=10 is Circle with (a,b)=(1,2),r=sqrt(10)