What is x^2+y^2+6x+8y+24=0 ?

The solution to x^2+y^2+6x+8y+24=0 is Circle with (a,b)=(-3,-4),r=1

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x^2+y^2+6x+8y+24=0

x^{2} + y^{2} + 6 x + 8 y + 24 = 0

(a, b) = (- 3, - 4), r = 1

Solution steps

x^{2} + y^{2} + 6 x + 8 y + 24 = 0

Rewrite

x^{2} + y^{2} + 6 x + 8 y + 24 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 4))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 4), r = 1

2 x^{2} + 2 y^{2} = 8

x^{2} + y^{2} - 4 x - 2 y - 4 = 0

x^{2} + (y + 2)^{2} = 36

(x + 5)^{2} + (y + 4)^{2} = 9

(x - 3)^{2} + (y + 2)^{2} = 3

What is x^2+y^2+6x+8y+24=0 ?
The solution to x^2+y^2+6x+8y+24=0 is Circle with (a,b)=(-3,-4),r=1