What is x^2+(y+2)^2=36 ?

The solution to x^2+(y+2)^2=36 is Circle with (a,b)=(0,-2),r=6

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x^2+(y+2)^2=36

x^{2} + (y + 2)^{2} = 36

(a, b) = (0, - 2), r = 6

Solution steps

x^{2} + (y + 2)^{2} = 36

Rewrite

x^{2} + (y + 2)^{2} = 36

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 2))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (0, - 2), r = 6

(x + 5)^{2} + (y + 4)^{2} = 9

(x - 3)^{2} + (y + 2)^{2} = 3

(x - 2)^{2} + (y - 3)^{2} = 25

\frac{2 x ^{2} + 2 y ^{2} - 3 x + 5 y - 3}{2} = 0

(x + 12)^{2} + (y - 4)^{2} - 30 = 0

What is x^2+(y+2)^2=36 ?
The solution to x^2+(y+2)^2=36 is Circle with (a,b)=(0,-2),r=6