What is (x-2)^2+(y-3)^2=25 ?

The solution to (x-2)^2+(y-3)^2=25 is Circle with (a,b)=(2,3),r=5

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(x-2)^2+(y-3)^2=25

(x - 2)^{2} + (y - 3)^{2} = 25

(a, b) = (2, 3), r = 5

Solution steps

(x - 2)^{2} + (y - 3)^{2} = 25

Rewrite

(x - 2)^{2} + (y - 3)^{2} = 25

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 5

\frac{2 x ^{2} + 2 y ^{2} - 3 x + 5 y - 3}{2} = 0

(x + 12)^{2} + (y - 4)^{2} - 30 = 0

6 x^{2} + 6 y^{2} - 24 x + 36 y = 72

x^{2} + y^{2} - 2 (x + y) > 0

2 x^{2} + 2 y^{2} + 6 x - 8 y + 12 = 0

What is (x-2)^2+(y-3)^2=25 ?
The solution to (x-2)^2+(y-3)^2=25 is Circle with (a,b)=(2,3),r=5