What is x^2+y^2-6=0 ?

The solution to x^2+y^2-6=0 is Circle with (a,b)=(0,0),r=sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-6=0

x^{2} + y^{2} - 6 = 0

(a, b) = (0, 0), r = 6

Solution steps

x^{2} + y^{2} - 6 = 0

Rewrite

x^{2} + y^{2} - 6 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 6

x^{2} + y^{2} = \frac{1}{4}

x^{2} + 8 x + y^{2} + 15 = 0

(x - 3)^{2} + (y + 3)^{2} = 6^{2}

4 x^{2} - 4 x + 4 y^{2} + 4 y = 9

x^{2} + y^{2} - 2 x + 6 y - 6 = 0

What is x^2+y^2-6=0 ?
The solution to x^2+y^2-6=0 is Circle with (a,b)=(0,0),r=sqrt(6)