What is 4x^2+4y^2=1 ?

The solution to 4x^2+4y^2=1 is Circle with (a,b)=(0,0),r= 1/2

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4x^2+4y^2=1

4 x^{2} + 4 y^{2} = 1

(a, b) = (0, 0), r = \frac{1}{2}

Solution steps

4 x^{2} + 4 y^{2} = 1

Rewrite

4 x^{2} + 4 y^{2} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{1}{2}

4 x^{2} + 4 y^{2} + 6 x - 8 y - 4 = 0

x^{2} + y^{2} - 10 x - 12 y - 3 = 0

x^{2} + y^{2} - 6 = 0

x^{2} + y^{2} = \frac{1}{4}

x^{2} + 8 x + y^{2} + 15 = 0

What is 4x^2+4y^2=1 ?
The solution to 4x^2+4y^2=1 is Circle with (a,b)=(0,0),r= 1/2