What is 2x^2+2y^2-14x+18y=7 ?

The solution to 2x^2+2y^2-14x+18y=7 is Circle with (a,b)=(7/2 ,-9/2),r=6

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2x^2+2y^2-14x+18y=7

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7

(a, b) = (\frac{7}{2}, - \frac{9}{2}), r = 6

Solution steps

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7

Rewrite

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7

in the form of the standard circle equation

(x - \frac{7}{2})^{2} + (y - (- \frac{9}{2}))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (\frac{7}{2}, - \frac{9}{2}), r = 6

x^{2} + y^{2} + 8 y = 3

x^{2} + y^{2} - 4 x - 6 y - 12 = 0

4 x^{2} + 12 x + 4 y^{2} + 16 y - 11 = 0

4 x^{2} + 4 y^{2} = 1

4 x^{2} + 4 y^{2} + 6 x - 8 y - 4 = 0

What is 2x^2+2y^2-14x+18y=7 ?
The solution to 2x^2+2y^2-14x+18y=7 is Circle with (a,b)=(7/2 ,-9/2),r=6