What is x^2+y^2+8y=3 ?

The solution to x^2+y^2+8y=3 is Circle with (a,b)=(0,-4),r=sqrt(19)

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x^2+y^2+8y=3

x^{2} + y^{2} + 8 y = 3

(a, b) = (0, - 4), r = 19

Solution steps

x^{2} + y^{2} + 8 y = 3

Rewrite

x^{2} + y^{2} + 8 y = 3

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 4))^{2} = (19)^{2}

Therefore the circle properties are:

(a, b) = (0, - 4), r = 19

x^{2} + y^{2} - 4 x - 6 y - 12 = 0

4 x^{2} + 12 x + 4 y^{2} + 16 y - 11 = 0

4 x^{2} + 4 y^{2} = 1

4 x^{2} + 4 y^{2} + 6 x - 8 y - 4 = 0

x^{2} + y^{2} - 10 x - 12 y - 3 = 0

What is x^2+y^2+8y=3 ?
The solution to x^2+y^2+8y=3 is Circle with (a,b)=(0,-4),r=sqrt(19)