What is 2x^2+2y^2+12x-2y-3=0 ?

The solution to 2x^2+2y^2+12x-2y-3=0 is Circle with (a,b)=(-3, 1/2),r=(sqrt(43))/2

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2x^2+2y^2+12x-2y-3=0

2 x^{2} + 2 y^{2} + 12 x - 2 y - 3 = 0

(a, b) = (- 3, \frac{1}{2}), r = \frac{43}{2}

Solution steps

2 x^{2} + 2 y^{2} + 12 x - 2 y - 3 = 0

Rewrite

2 x^{2} + 2 y^{2} + 12 x - 2 y - 3 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - \frac{1}{2})^{2} = (\frac{43}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, \frac{1}{2}), r = \frac{43}{2}

x^{2} + y^{2} + 8 x - 9 y = 6

2 x^{2} + 2 y^{2} - 14 x + 18 y = 7

x^{2} + y^{2} + 8 y = 3

x^{2} + y^{2} - 4 x - 6 y - 12 = 0

4 x^{2} + 12 x + 4 y^{2} + 16 y - 11 = 0

What is 2x^2+2y^2+12x-2y-3=0 ?
The solution to 2x^2+2y^2+12x-2y-3=0 is Circle with (a,b)=(-3, 1/2),r=(sqrt(43))/2