What is the axis y=5x^2-12x+7 ?

The axis y=5x^2-12x+7 is x= 6/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=5x^2-12x+7

axis

y = 5 x^{2} - 12 x + 7

x = \frac{6}{5}

Solution steps

y = 5 x^{2} - 12 x + 7

Rewrite

y = 5 x^{2} - 12 x + 7

in the standard form

4 \cdot \frac{1}{20} (y - (- \frac{1}{5})) = (x - \frac{6}{5})^{2}

Therefore parabola properties are:

(h, k) = (\frac{6}{5}, - \frac{1}{5}), p = \frac{1}{20}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{6}{5}

x^{2} - 6 x - 4 y = - 1

y = + x^{2} + 3 x - 5

y = 4 - x (x + 3)

y^{2} = 16 - 4 x

y = + (x + 5)^{2} + 3