What is the axis x^2-6x-4y=-1 ?

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axis x^2-6x-4y=-1

axis

x^{2} - 6 x - 4 y = - 1

x = 3

Solution steps

x^{2} - 6 x - 4 y = - 1

Rewrite

x^{2} - 6 x - 4 y = - 1

in the standard form

4 \cdot 1 \cdot (y - (- 2)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 2), p = 1

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

y = + x^{2} + 3 x - 5

y = 4 - x (x + 3)

y^{2} = 16 - 4 x

y = + (x + 5)^{2} + 3

y^{2} - 8 x - 6 y - 3 = 0