What is the axis y=4-x(x+3) ?

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axis y=4-x(x+3)

axis

y = 4 - x (x + 3)

x = - \frac{3}{2}

Solution steps

y = 4 - x (x + 3)

Rewrite

y = 4 - x (x + 3)

in the standard form

4 (- \frac{1}{4}) (y - \frac{25}{4}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{25}{4}), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{3}{2}

y^{2} = 16 - 4 x

y = + (x + 5)^{2} + 3

y^{2} - 8 x - 6 y - 3 = 0

y = 6 x^{2} + 10 x - 4

y = - 2 x^{2} + 16 x - 31