What is the axis y=6x^2+10x-4 ?

The axis y=6x^2+10x-4 is x=-5/6

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axis y=6x^2+10x-4

axis

y = 6 x^{2} + 10 x - 4

x = - \frac{5}{6}

Solution steps

y = 6 x^{2} + 10 x - 4

Rewrite

y = 6 x^{2} + 10 x - 4

in the standard form

4 \cdot \frac{1}{24} (y - (- \frac{49}{6})) = (x - (- \frac{5}{6}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{6}, - \frac{49}{6}), p = \frac{1}{24}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{5}{6}

y = - 2 x^{2} + 16 x - 31

y = 4 x^{2} + x + 1

y = + 1 - x - x^{2}

x = \frac{y ^{2}}{8}

y = 18 x^{2} - 14 x + 9