What is the axis y=+x^2-12x+35 ?

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axis y=+x^2-12x+35

axis

y = + x^{2} - 12 x + 35

x = 6

Solution steps

y = x^{2} - 12 x + 35

Rewrite

y = x^{2} - 12 x + 35

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, - 1), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 6

y = - 3 x^{2} - 6 x + 8

y = 2 (x - 2)^{2} + 9

y = x^{2} (0.1)

y = x^{2} - x + 1

y = \frac{1}{2} x^{2} - 3