What is the axis y=-3x^2-6x+8 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=-3x^2-6x+8

axis

y = - 3 x^{2} - 6 x + 8

x = - 1

Solution steps

y = - 3 x^{2} - 6 x + 8

Rewrite

y = - 3 x^{2} - 6 x + 8

in the standard form

4 (- \frac{1}{12}) (y - 11) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, 11), p = - \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y = 2 (x - 2)^{2} + 9

y = x^{2} (0.1)

y = x^{2} - x + 1

y = \frac{1}{2} x^{2} - 3

y^{2} - 8 x = 0