What is the axis y= 1/2 x^2-3 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y= 1/2 x^2-3

axis

y = \frac{1}{2} x^{2} - 3

x = 0

Solution steps

y = \frac{1}{2} x^{2} - 3

Rewrite

y = \frac{1}{2} x^{2} - 3

in the standard form:

4 \cdot \frac{1}{2} (y - (- 3)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 3), p = \frac{1}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y^{2} - 8 x = 0

y = 18 x - \frac{3}{2} x^{2}

x = - \frac{1}{2} (y + 4)^{2} - 5

(y - 2)^{2} = - (x + 4)

y = 3 (x - 1) (x + 2)