What is the axis y=6x^2-13x+6 ?

The axis y=6x^2-13x+6 is x= 13/12

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axis y=6x^2-13x+6

axis

y = 6 x^{2} - 13 x + 6

x = \frac{13}{12}

Solution steps

y = 6 x^{2} - 13 x + 6

Rewrite

y = 6 x^{2} - 13 x + 6

in the standard form

4 \cdot \frac{1}{24} (y - (- \frac{25}{24})) = (x - \frac{13}{12})^{2}

Therefore parabola properties are:

(h, k) = (\frac{13}{12}, - \frac{25}{24}), p = \frac{1}{24}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{13}{12}

y = 3 x^{2} + 19 x - 40

(x + 5)^{2} = - 2 (y - 2)

x^{2} = - 36 y

y = + x^{2} - 12 x + 35

y = - 3 x^{2} - 6 x + 8