What is x^2+y^2+8y=33 ?

The solution to x^2+y^2+8y=33 is Circle with (a,b)=(0,-4),r=7

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x^2+y^2+8y=33

x^{2} + y^{2} + 8 y = 33

(a, b) = (0, - 4), r = 7

Solution steps

x^{2} + y^{2} + 8 y = 33

Rewrite

x^{2} + y^{2} + 8 y = 33

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 4))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (0, - 4), r = 7

x^{2} + 2 x + y^{2} - 35 = 0

x^{2} + y^{2} + 12 x - 8 y + 3 = 0

8 x^{2} + 8 y^{2} - 20 x + 64 y - 371 = 0

x^{2} + y^{2} + 10 x - 2 y - 10 = 0

\frac{4}{3} x^{2} + \frac{4}{3} y^{2} = 1

What is x^2+y^2+8y=33 ?
The solution to x^2+y^2+8y=33 is Circle with (a,b)=(0,-4),r=7