What is 8x^2+8y^2-20x+64y-371=0 ?

The solution to 8x^2+8y^2-20x+64y-371=0 is Circle with (a,b)=(5/4 ,-4),r=(sqrt(1023))/4

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8x^2+8y^2-20x+64y-371=0

8 x^{2} + 8 y^{2} - 20 x + 64 y - 371 = 0

(a, b) = (\frac{5}{4}, - 4), r = \frac{1023}{4}

Solution steps

8 x^{2} + 8 y^{2} - 20 x + 64 y - 371 = 0

Rewrite

8 x^{2} + 8 y^{2} - 20 x + 64 y - 371 = 0

in the form of the standard circle equation

(x - \frac{5}{4})^{2} + (y - (- 4))^{2} = (\frac{1023}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{4}, - 4), r = \frac{1023}{4}

x^{2} + y^{2} + 10 x - 2 y - 10 = 0

\frac{4}{3} x^{2} + \frac{4}{3} y^{2} = 1

y^{2} + z^{2} = 1

x^{2} + y^{2} + 4 x + 3 = 0

x^{2} + (y - 1)^{2} = 4

What is 8x^2+8y^2-20x+64y-371=0 ?
The solution to 8x^2+8y^2-20x+64y-371=0 is Circle with (a,b)=(5/4 ,-4),r=(sqrt(1023))/4