What is 4/3 x^2+4/3 y^2=1 ?

The solution to 4/3 x^2+4/3 y^2=1 is Circle with (a,b)=(0,0),r=(sqrt(3))/2

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4/3 x^2+4/3 y^2=1

\frac{4}{3} x^{2} + \frac{4}{3} y^{2} = 1

(a, b) = (0, 0), r = \frac{3}{2}

Solution steps

\frac{4}{3} x^{2} + \frac{4}{3} y^{2} = 1

Rewrite

\frac{4}{3} x^{2} + \frac{4}{3} y^{2} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{3}{2}

y^{2} + z^{2} = 1

x^{2} + y^{2} + 4 x + 3 = 0

x^{2} + (y - 1)^{2} = 4

x^{2} + y^{2} + 8 x - 14 y + 1 = 0

x^{2} + y^{2} - 5 x + 4 y = 46

What is 4/3 x^2+4/3 y^2=1 ?
The solution to 4/3 x^2+4/3 y^2=1 is Circle with (a,b)=(0,0),r=(sqrt(3))/2