What is the range of 2+arctan(x-1) ?

The range of 2+arctan(x-1) is -pi/2+2<f(x)< pi/2+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of 2+arctan(x-1)

range

2 + arctan (x - 1)

- \frac{π}{2} + 2 < f (x) < \frac{π}{2} + 2

Interval Notation

(- \frac{π}{2} + 2, \frac{π}{2} + 2)

Solution steps

The range of the basic

arctan

function is

- \frac{π}{2} < arctan (x - 1) < \frac{π}{2}

- \frac{π}{2} < arctan (x - 1) < \frac{π}{2}

Add to the edges of the range:

2

- \frac{π}{2} + 2 < arctan (x - 1) + 2 < \frac{π}{2} + 2

Therefore the range is

- \frac{π}{2} + 2 < f (x) < \frac{π}{2} + 2

y - 6 x = 9

0 = 3 x - 6

f (x) = ∣ 3 x - 2 ∣

e^{\frac{( x - 1 ) ^{2}}{2}}

f (x) = \frac{x ^{3}}{3} - 3 x^{2} - 7 x

What is the range of 2+arctan(x-1) ?
The range of 2+arctan(x-1) is -pi/2+2<f(x)< pi/2+2