What is the inflection f(x)=(x^3)/3-3x^2-7x ?

The inflection f(x)=(x^3)/3-3x^2-7x is (3,-39)

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inflection f(x)=(x^3)/3-3x^2-7x

inflection points

f (x) = \frac{x ^{3}}{3} - 3 x^{2} - 7 x

(3, - 39)

Solution steps

f^{''} (x) = 2 x - 6

Find intervals:

Concave Downward

: - \infty < x < 3,

Concave Upward

: 3 < x < \infty

Plug

x = 3

into

\frac{x ^{3}}{3} - 3 x^{2} - 7 x : - 39

(3, - 39)

What is the inflection f(x)=(x^3)/3-3x^2-7x ?
The inflection f(x)=(x^3)/3-3x^2-7x is (3,-39)