What is the critical X^2-5X+7 ?

The critical X^2-5X+7 is X= 5/2

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critical X^2-5X+7

critical points

X^{2} - 5 X + 7

X = \frac{5}{2}

Solution steps

X^{2} - 5 X + 7

Find where

f^{'} (X)

is equal to zero or undefined

X = \frac{5}{2}

Identify critical points not in

f (X)

domain

Domain of

X^{2} - 5 X + 7 : - \infty < X < \infty

All critical points are in domain

X = \frac{5}{2}

(7 - 6 x) e^{x}

(9, - 3), (- 2, - 2)

f (x) = 6^{x}

\frac{2}{5} sin (x)

f (x) = 5 x - 4 y = 30