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Popular >

distance (9,-3),(-2,-2)

Solution

distance

(9, - 3), (- 2, - 2)

Solution

122

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(9, - 3)

and

(- 2, - 2)

is

= (- 2 - 9)^{2} + (- 2 - (- 3))^{2}

Simplify

= 122

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f (x) = 6^{x}

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\frac{2}{5} sin (x)

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f (x) = 5 x - 4 y = 30

critical f(x)=x^3-6x^2-15x+40 critical points

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domain of f(x)=((x^2-1))/(x^2+1)domain

f (x) = \frac{( x ^{2} - 1 )}{x ^{2} + 1}

Frequently Asked Questions (FAQ)

What is the distance (9,-3),(-2,-2) ?
The distance (9,-3),(-2,-2) is square root of 122