What is the inverse of f(x)=(2x^2-7x+2)/(x-4) ?

The inverse of f(x)=(2x^2-7x+2)/(x-4) is (7+x+sqrt(x^2-18x+33))/4 ,(7+x-sqrt(x^2-18x+33))/4

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inverse of f(x)=(2x^2-7x+2)/(x-4)

inverse

f (x) = \frac{2 x ^{2} - 7 x + 2}{x - 4}

\frac{7 + x + x ^{2} - 18 x + 33}{4}, \frac{7 + x - x ^{2} - 18 x + 33}{4}

Solution steps

y = \frac{2 x ^{2} - 7 x + 2}{x - 4}

Replace

x

with

y

x = \frac{2 y ^{2} - 7 y + 2}{y - 4}

Solve for

y, x = \frac{2 y ^{2} - 7 y + 2}{y - 4}

\frac{7 + x + x ^{2} - 18 x + 33}{4}, \frac{7 + x - x ^{2} - 18 x + 33}{4}

f (x) = x^{\frac{6}{5}} - 12 x^{\frac{1}{5}}

- 3 x - 2 y = 6

x^{2} + y - 25 = 0

f (x) = \frac{2 x}{x ^{2} + 81}

- lo g_{2} (3 x - 5)

What is the inverse of f(x)=(2x^2-7x+2)/(x-4) ?
The inverse of f(x)=(2x^2-7x+2)/(x-4) is (7+x+sqrt(x^2-18x+33))/4 ,(7+x-sqrt(x^2-18x+33))/4