What is the extreme f(x)=x^{6/5}-12x^{1/5} ?

The extreme f(x)=x^{6/5}-12x^{1/5} is Minimum(2,-10*2^{1/5})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^{6/5}-12x^{1/5}

extreme points

f (x) = x^{\frac{6}{5}} - 12 x^{\frac{1}{5}}

Minimum (2, - 10 \cdot 2^{\frac{1}{5}})

Solution steps

f^{'} (x) = \frac{6 x - 12}{5 x ^{\frac{4}{5}}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{\frac{6}{5}} - 12 x^{\frac{1}{5}} : - 10 \cdot 2^{\frac{1}{5}}

Minimum (2, - 10 \cdot 2^{\frac{1}{5}})

- 3 x - 2 y = 6

x^{2} + y - 25 = 0

f (x) = \frac{2 x}{x ^{2} + 81}

- lo g_{2} (3 x - 5)

y = 2^{- x}

What is the extreme f(x)=x^{6/5}-12x^{1/5} ?
The extreme f(x)=x^{6/5}-12x^{1/5} is Minimum(2,-10*2^{1/5})