What is the range of 1-cos(x) ?

The range of 1-cos(x) is 0<= f(x)<= 2

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range of 1-cos(x)

range

1 - cos (x)

0 \leq f (x) \leq 2

Interval Notation

[0, 2]

Solution steps

The range of the basic

cos

function is

- 1 \leq cos (x) \leq 1

- 1 \leq cos (x) \leq 1

Multiply the edges of the range by:

- 1

- 1 \leq - cos (x) \leq 1

Add to the edges of the range:

1

0 \leq - cos (x) + 1 \leq 2

Therefore the range is

0 \leq f (x) \leq 2

y = 4 x - 2, (5, - 11)

f (x) = - x^{2} - 2 x + 3

y = \frac{2 x + 11}{3 x + 19}

f (x) = 13 x - 3

f (x) = \frac{5 x + 3}{3 x - 8}