What is the inverse of y=(2x+11)/(3x+19) ?

The inverse of y=(2x+11)/(3x+19) is (11-19x)/(3x-2)

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inverse of y=(2x+11)/(3x+19)

inverse

y = \frac{2 x + 11}{3 x + 19}

\frac{11 - 19 x}{3 x - 2}

Solution steps

y = \frac{2 x + 11}{3 x + 19}

Replace

x

with

y

x = \frac{2 y + 11}{3 y + 19}

Solve for

y, x = \frac{2 y + 11}{3 y + 19}

\frac{11 - 19 x}{3 x - 2}

f (x) = 13 x - 3

f (x) = \frac{5 x + 3}{3 x - 8}

g (x) = - 3 x^{2} - 5

f (x) = 6 x^{3} - 3 x^{2} + x - 2

(6, - 2), (4, 6)

What is the inverse of y=(2x+11)/(3x+19) ?
The inverse of y=(2x+11)/(3x+19) is (11-19x)/(3x-2)