What is the extreme f(x)=2x^3+12x^2-30x ?

The extreme f(x)=2x^3+12x^2-30x is Maximum(-5,200),Minimum(1,-16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=2x^3+12x^2-30x

extreme points

f (x) = 2 x^{3} + 12 x^{2} - 30 x

Maximum (- 5, 200), Minimum (1, - 16)

Solution steps

f^{'} (x) = 6 x^{2} + 24 x - 30

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 5

into

2 x^{3} + 12 x^{2} - 30 x : 200

Maximum (- 5, 200)

Plug

x = 1

into

2 x^{3} + 12 x^{2} - 30 x : - 16

Minimum (1, - 16)

Maximum (- 5, 200), Minimum (1, - 16)

What is the extreme f(x)=2x^3+12x^2-30x ?
The extreme f(x)=2x^3+12x^2-30x is Maximum(-5,200),Minimum(1,-16)