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midpoint
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domain of f(x)=sqrt(1-5^t)range of f(x)=(6-x)^{1/8}intercepts of f(x)=-(x+1)^2+4inverse of sin(2x)symmetry x^2+2x
Frequently Asked Questions (FAQ)
What is the midpoint (-2,-4),(4,6) ?
The midpoint (-2,-4),(4,6) is (1,1)