What is the inverse of 1/(14.9)x^2 ?

The inverse of 1/(14.9)x^2 is sqrt(14.9)sqrt(x),-sqrt(14.9)sqrt(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of 1/(14.9)x^2

inverse

\frac{1}{14.9} x^{2}

14.9 x, - 14.9 x

Solution steps

y = \frac{1}{14.9} x^{2}

Replace

x

with

y

x = \frac{1}{14.9} y^{2}

Solve for

y, x = \frac{1}{14.9} y^{2}

14.9 x, - 14.9 x

2 x + y = 5, (5, 7)

f (x) = \frac{2 x - 1}{2 x + 7}

e^{x + 8} + 3

f (x) = 3 (0.5)^{x}

\frac{4 x ^{2} - 4 x + 5}{2 x - 20}

What is the inverse of 1/(14.9)x^2 ?
The inverse of 1/(14.9)x^2 is sqrt(14.9)sqrt(x),-sqrt(14.9)sqrt(x)