What is the perpendicular 2x+y=5,(5,7) ?

The perpendicular 2x+y=5,(5,7) is y= 1/2 x+9/2

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perpendicular 2x+y=5,(5,7)

perpendicular

2 x + y = 5, (5, 7)

y = \frac{1}{2} x + \frac{9}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

2 x + y = 5

that passes through

(5, 7)

Find the slope of

2 x + y = 5 : m = - 2

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(5, 7) : y = \frac{1}{2} x + \frac{9}{2}

y = \frac{1}{2} x + \frac{9}{2}

f (x) = \frac{2 x - 1}{2 x + 7}

e^{x + 8} + 3

f (x) = 3 (0.5)^{x}

\frac{4 x ^{2} - 4 x + 5}{2 x - 20}

f (x) = \frac{x - 12}{x ^{3} + x}

What is the perpendicular 2x+y=5,(5,7) ?
The perpendicular 2x+y=5,(5,7) is y= 1/2 x+9/2