What is the domain of f(x)= 7/(sqrt(x-9)) ?

The domain of f(x)= 7/(sqrt(x-9)) is x>9

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domain of f(x)= 7/(sqrt(x-9))

domain

f (x) = \frac{7}{x - 9}

x > 9

Interval Notation

(9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

x > 9

f (x) = (x - 4)^{2} - \frac{2}{3} = 6 y - 12

(2.6, 1.3), (1.6, - 5.7)

f (x) = 3 x - 4 y = 12

y = - 6 x - 18

y = 4 x - 7

What is the domain of f(x)= 7/(sqrt(x-9)) ?
The domain of f(x)= 7/(sqrt(x-9)) is x>9