What is the inverse of f(x)=(x-4)^2-2/3 =6y-12 ?

The inverse of f(x)=(x-4)^2-2/3 =6y-12 is (y+12)/6

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inverse of f(x)=(x-4)^2-2/3 =6y-12

inverse

f (x) = (x - 4)^{2} - \frac{2}{3} = 6 y - 12

\frac{y + 12}{6}

Solution steps

x = 6 y - 12

Replace

y

with

x

y = 6 x - 12

Solve for

x, y = 6 x - 12

\frac{y + 12}{6}

(2.6, 1.3), (1.6, - 5.7)

f (x) = 3 x - 4 y = 12

y = - 6 x - 18

y = 4 x - 7

f (x) = - x^{2} + 11

What is the inverse of f(x)=(x-4)^2-2/3 =6y-12 ?
The inverse of f(x)=(x-4)^2-2/3 =6y-12 is (y+12)/6