What is the domain of f(x)= x/(\sqrt[4]{16-x^2)} ?

The domain of f(x)= x/(\sqrt[4]{16-x^2)} is -4<x<4

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domain of f(x)= x/(\sqrt[4]{16-x^2)}

domain

- 4 < x < 4

Interval Notation

(- 4, 4)

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq 4

Find undefined (singularity) points:

x = 4, x = - 4

Combine real regions and undefined points for final function domain

- 4 < x < 4

y = - \frac{5}{7} x + \frac{11}{7}, (5, - 2)

\frac{1}{3 x - 2}

f (x) = y^{2} + x - 9 = 0

X + 3

f (x) = x^{2} - 4 x - 7

What is the domain of f(x)= x/(\sqrt[4]{16-x^2)} ?
The domain of f(x)= x/(\sqrt[4]{16-x^2)} is -4<x<4