What is the inverse of f(x)=x^2-4x-7 ?

The inverse of f(x)=x^2-4x-7 is 2+sqrt(x+11),2-sqrt(x+11)

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inverse of f(x)=x^2-4x-7

inverse

f (x) = x^{2} - 4 x - 7

2 + x + 11, 2 - x + 11

Solution steps

y = x^{2} - 4 x - 7

Replace

x

with

y

x = y^{2} - 4 y - 7

Solve for

y, x = y^{2} - 4 y - 7

2 + x + 11, 2 - x + 11

4 x - 2 y = - 8

y = - 2 x^{2} + 8 x - 1

f (x) = sin (x + 5) - 3

2 x^{4} + 8 x^{3}

y = x^{2} - 7

What is the inverse of f(x)=x^2-4x-7 ?
The inverse of f(x)=x^2-4x-7 is 2+sqrt(x+11),2-sqrt(x+11)