What is the critical f(x)=(x^3)/(x+4) ?

The critical f(x)=(x^3)/(x+4) is x=-6,x=0

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critical f(x)=(x^3)/(x+4)

critical points

f (x) = \frac{x ^{3}}{x + 4}

x = - 6, x = 0

Solution steps

\frac{x ^{3}}{x + 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 6, x = 0, x = - 4

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{x + 4} : x < - 4 or x > - 4

\frac{x ^{3}}{x + 4}

is not defined at

x = - 4

, therefore:

x = - 6, x = 0

What is the critical f(x)=(x^3)/(x+4) ?
The critical f(x)=(x^3)/(x+4) is x=-6,x=0