What is the critical x/(\sqrt[3]{x^2-1)} ?

The critical x/(\sqrt[3]{x^2-1)} is x=-sqrt(3),x=sqrt(3)

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critical x/(\sqrt[3]{x^2-1)}

critical points

x = - 3, x = 3

Solution steps

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

is not defined at

x = - 1, x = 1

, therefore:

x = - 3, x = 3

What is the critical x/(\sqrt[3]{x^2-1)} ?
The critical x/(\sqrt[3]{x^2-1)} is x=-sqrt(3),x=sqrt(3)