What is the domain of f(x)=sqrt(x^2-1) ?

The domain of f(x)=sqrt(x^2-1) is x = 1

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domain of f(x)=sqrt(x^2-1)

domain

f (x) = x^{2} - 1

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

f (x) = - 2 (x + 3)^{2} - 1

(2 x - 8)^{\frac{2}{3}}

f (x) = \frac{( 3 x - 3 )}{x + 6}

- x^{2} + 2 x - 1

(- 1, 1), (- 2, - 1)

What is the domain of f(x)=sqrt(x^2-1) ?
The domain of f(x)=sqrt(x^2-1) is x<=-1\lor x>= 1