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Popular >

midpoint (-1,1),(-2,-1)

Solution

midpoint

(- 1, 1), (- 2, - 1)

Solution

(- \frac{3}{2}, 0)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 1, 1), (x_{2}, y_{2}) = (- 2, - 1)

= (\frac{- 2 - 1}{2}, \frac{- 1 + 1}{2})

Refine

= (- \frac{3}{2}, 0)

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6 x - x^{2} - 5

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f (x) = e^{- t}

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x^{2} - 8 x + 12

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distance (0,3),(3,0)distance

(0, 3), (3, 0)

Frequently Asked Questions (FAQ)

What is the midpoint (-1,1),(-2,-1) ?
The midpoint (-1,1),(-2,-1) is (-3/2 ,0)