What is the range of cot(1/2 x) ?

The range of cot(1/2 x) is -infinity <f(x)<infinity

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range of cot(1/2 x)

range

cot (\frac{1}{2} x)

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The range of the basic

cot

function is

- \infty < cot (\frac{1}{2} x) < \infty

- \infty < cot (\frac{1}{2} x) < \infty

Therefore the range is

- \infty < f (x) < \infty

2^{x} - 8

f (x) = 36 - x^{2}

f (x) = \frac{1}{( x - 3 )}

\frac{25}{y - 9}

f (x) = 2^{x} - 2

What is the range of cot(1/2 x) ?
The range of cot(1/2 x) is -infinity <f(x)<infinity