What is the inverse of f(x)=sqrt(36-x^2) ?

The inverse of f(x)=sqrt(36-x^2) is sqrt(-x^2+36),-sqrt(-x^2+36)

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inverse of f(x)=sqrt(36-x^2)

inverse

f (x) = 36 - x^{2}

- x^{2} + 36, - - x^{2} + 36

Solution steps

y = 36 - x^{2}

Replace

x

with

y

x = 36 - y^{2}

Solve for

y, x = 36 - y^{2}

- x^{2} + 36, - - x^{2} + 36

f (x) = \frac{1}{( x - 3 )}

\frac{25}{y - 9}

f (x) = 2^{x} - 2

f (x) = 2 + \frac{1}{x + 3}

\frac{x ^{3} - 16 x}{4 x ^{2} - 12 x}

What is the inverse of f(x)=sqrt(36-x^2) ?
The inverse of f(x)=sqrt(36-x^2) is sqrt(-x^2+36),-sqrt(-x^2+36)