What is the asymptotes of f(x)=(x^2-9)/(3x+6) ?

The asymptotes of f(x)=(x^2-9)/(3x+6) is Vertical: x=-2,Slant: y= 1/3 x-2/3

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asymptotes of f(x)=(x^2-9)/(3x+6)

asymptotes

f (x) = \frac{x ^{2} - 9}{3 x + 6}

Vertical : x = - 2, Slant : y = \frac{1}{3} x - \frac{2}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 9}{3 x + 6} : x = - 2

Horizontal Asymptotes of

\frac{x ^{2} - 9}{3 x + 6} :

None

Slant Asymptotes of

\frac{x ^{2} - 9}{3 x + 6} : y = \frac{1}{3} x - \frac{2}{3}

Vertical : x = - 2, Slant : y = \frac{1}{3} x - \frac{2}{3}

f (x) = (x + 3)^{2} - 2

y = ln (x - 1) - ln (2) - 1

4 y = 36

f (x) = 2 x - 4 sin (x), 0 \leq x \leq 2 π

f (x) = x^{4} + 2 x^{2}

What is the asymptotes of f(x)=(x^2-9)/(3x+6) ?
The asymptotes of f(x)=(x^2-9)/(3x+6) is Vertical: x=-2,Slant: y= 1/3 x-2/3