{
"query": {
"display": "inverse $$f\\left(x\\right)=\\left(x+3\\right)^{2}-2$$",
"symbolab_question": "FUNCTION#inverse f(x)=(x+3)^{2}-2"
},
"solution": {
"level": "PERFORMED",
"subject": "Functions & Graphing",
"topic": "Functions",
"subTopic": "inverse",
"default": "\\sqrt{x+2}-3,-\\sqrt{x+2}-3",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "Inverse of $$\\left(x+3\\right)^{2}-2:{\\quad}\\sqrt{x+2}-3,\\:-\\sqrt{x+2}-3$$",
"steps": [
{
"type": "definition",
"title": "Function Inverse definition",
"text": "A function g is the inverse of function f if for $$y=f\\left(x\\right),\\:\\:x=g\\left(y\\right)\\:$$"
},
{
"type": "step",
"result": "y=\\left(x+3\\right)^{2}-2"
},
{
"type": "interim",
"title": "Replace $$x\\:$$with $$y$$",
"input": "y=\\left(x+3\\right)^{2}-2",
"result": "x=\\left(y+3\\right)^{2}-2",
"steps": [
{
"type": "step",
"primary": "Replace $$x\\:$$with $$y$$",
"secondary": [
"Replace $$y\\:$$with $$x$$"
],
"result": "x=\\left(y+3\\right)^{2}-2"
}
],
"meta": {
"interimType": "Interchange Variables 2Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7vpqcDD/7yX5Tbd9fO9JFZdY7iMyUU3WTUlVAKVk9b4b4KqpqHsTkSBgy/axoI6DamTAUhNuvP+oYRx2ZQG6x18Q3tfXX1jSRYh4EFIfu+U5DNOwm/hV0YV0QkO8wKai7EaTcoaJcD/yzWbRAAledhROjRxpO2XYmGPYDdnsqYeQ="
}
},
{
"type": "interim",
"title": "Solve for $$y,\\:x=\\left(y+3\\right)^{2}-2$$",
"input": "x=\\left(y+3\\right)^{2}-2",
"steps": [
{
"type": "step",
"primary": "Switch sides",
"result": "\\left(y+3\\right)^{2}-2=x"
},
{
"type": "interim",
"title": "Move $$2\\:$$to the right side",
"input": "\\left(y+3\\right)^{2}-2=x",
"result": "\\left(y+3\\right)^{2}=x+2",
"steps": [
{
"type": "step",
"primary": "Add $$2$$ to both sides",
"result": "\\left(y+3\\right)^{2}-2+2=x+2"
},
{
"type": "step",
"primary": "Simplify",
"result": "\\left(y+3\\right)^{2}=x+2"
}
],
"meta": {
"interimType": "Move to the Right Title 1Eq",
"gptData": "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"
}
},
{
"type": "step",
"primary": "For $$\\left(g\\left(x\\right)\\right)^{2}=f\\left(a\\right)$$ the solutions are $$g\\left(x\\right)=\\sqrt{f\\left(a\\right)},\\:\\:-\\sqrt{f\\left(a\\right)}$$"
},
{
"type": "interim",
"title": "Solve $$y+3=\\sqrt{x+2}:{\\quad}y=\\sqrt{x+2}-3$$",
"input": "y+3=\\sqrt{x+2}",
"steps": [
{
"type": "interim",
"title": "Move $$3\\:$$to the right side",
"input": "y+3=\\sqrt{x+2}",
"result": "y=\\sqrt{x+2}-3",
"steps": [
{
"type": "step",
"primary": "Subtract $$3$$ from both sides",
"result": "y+3-3=\\sqrt{x+2}-3"
},
{
"type": "step",
"primary": "Simplify",
"result": "y=\\sqrt{x+2}-3"
}
],
"meta": {
"interimType": "Move to the Right Title 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "interim",
"title": "Solve $$y+3=-\\sqrt{x+2}:{\\quad}y=-\\sqrt{x+2}-3$$",
"input": "y+3=-\\sqrt{x+2}",
"steps": [
{
"type": "interim",
"title": "Move $$3\\:$$to the right side",
"input": "y+3=-\\sqrt{x+2}",
"result": "y=-\\sqrt{x+2}-3",
"steps": [
{
"type": "step",
"primary": "Subtract $$3$$ from both sides",
"result": "y+3-3=-\\sqrt{x+2}-3"
},
{
"type": "step",
"primary": "Simplify",
"result": "y=-\\sqrt{x+2}-3"
}
],
"meta": {
"interimType": "Move to the Right Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7XUtKmNmSXlE7Xb5YTv9tkxzi1TbVgx+IgAMCOn+S1j/yxv83nWcSQlsRHYjYisgmOjsPs+HmSooIK4AFAIsqBqJmlSrZ/3f5s6dVhaC2CrXtQ3syg1Vk4donCZ9RNqWUA3c2uJJlFzWGT1Wm3enJ6tIWMxer8Y0maDEiJwmPzz0Gzvef9somTq4fFXcfzhz7SLX4UBH/S/s/eJ2lZb/sgEAsHGn2hBXLlTrEuGZfbDrJp2jLGfG0O/kGO2/e3utk7DJbUyO4Y9hnrE34KvVUceCDCH2DcDNialMuvy7Bnwnk+UY9JBE5v/YSZ6s+GczznYqnACvNSqOPyqchT4gmfHabZwi5JytN/1ufmQiSimkGMgSS9o9O+UehR1a3T1ITWnYMM7mOiW9HKIEiHilarlHG4pyteBqJ+X90AXJ/ySqNExtrjbhm1J/jIJkSucTEu8fVrwsgbvn+RhPU/QszNpXozo++AUEe5BUhdXupbD0kt3WiGR7ZaCaXvz77bMjS"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "step",
"primary": "The solutions to the quadratic equation are:",
"result": "y=\\sqrt{x+2}-3,\\:y=-\\sqrt{x+2}-3"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve For Title 2Eq"
}
},
{
"type": "step",
"result": "\\sqrt{x+2}-3,\\:-\\sqrt{x+2}-3"
}
],
"meta": {
"solvingClass": "Function Inverse"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "(x+3)^{2}-2"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
inverse
Solution
Solution steps
Replace with
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Frequently Asked Questions (FAQ)
What is the inverse of f(x)=(x+3)^2-2 ?
The inverse of f(x)=(x+3)^2-2 is sqrt(x+2)-3,-sqrt(x+2)-3