What is the critical f(x)=49x^3-3x ?

The critical f(x)=49x^3-3x is x=-1/7 ,x= 1/7

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critical f(x)=49x^3-3x

critical points

f (x) = 49 x^{3} - 3 x

x = - \frac{1}{7}, x = \frac{1}{7}

Solution steps

49 x^{3} - 3 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{7}, x = \frac{1}{7}

Identify critical points not in

f (x)

domain

Domain of

49 x^{3} - 3 x : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{7}, x = \frac{1}{7}

f (x) = 8 x^{2} - 8

2 x^{2} - 17

y = 15

y = 4 x + 2, at 2, 2

f (x) = 5 x^{2} - 2

What is the critical f(x)=49x^3-3x ?
The critical f(x)=49x^3-3x is x=-1/7 ,x= 1/7