What is the perpendicular y=4x+2,\at 2,2 ?

The perpendicular y=4x+2,\at 2,2 is y=-1/4 x+b

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perpendicular y=4x+2,\at 2,2

perpendicular

y = 4 x + 2, at 2, 2

y = - \frac{1}{4} x + b

Solution steps

Find the slope of

y = 4 x + 2 : m = 4

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{4}

Line with slope m=

- \frac{1}{4} : y = - \frac{1}{4} x + b

y = - \frac{1}{4} x + b

f (x) = 5 x^{2} - 2

f (x) = - 30 x^{2} + 28 x - 6

f (x) = \frac{x - 3}{x ^{2} - 4}

\frac{36}{x ^{2}}

f (x) = \frac{16 x ^{2}}{x ^{4} + 64}

What is the perpendicular y=4x+2,\at 2,2 ?
The perpendicular y=4x+2,\at 2,2 is y=-1/4 x+b